How to replace all elements that are not even integers?
显示 更早的评论
need to generate an array with 20 random integers, and replace all that are not even with another random integer
v=randi([10 30],1,20)
v1 = 0;
N = -1;
while N<0
N = 1;
for k = 1:20
if(~rem(v(k),2))
v1(k) = v(k);
end
end
end
2 个评论
James Tursa
2018-3-30
编辑：James Tursa
2018-3-30
Where is your "replacing" code? I don't see any code under your "not even" test that generates another replacement random integer. Also, you should double check your "not even" test to make sure it is doing what you think it is doing. How is the N variable connected to your algorithm? I don't see any connection.
edward wiltz
2018-3-30
编辑：edward wiltz
2018-3-30
采纳的回答
Birdman
2018-3-30
This should help:
N=20;idx=1:N;
while true
v(idx)=randi([10 30],1,N);
if all(mod(v,2)==0)
break;
else
idx=find(mod(v,2)~=0);
N=numel(idx);
v(idx)=0;
end
end
更多回答（1 个）
David Fletcher
2018-3-30
A different way of doing it - generate a list of random integers much larger than the number you need, and pick out the subset of even numbers. Generate another list of random indices and use that to pick out 20 even numbers from the subset of even 'random' numbers (or just pick out the first 20 - I'm not sure it would make much difference)
list=randi([1 100],1,1000)
evenIndices=mod(list,2)==0
evenNums=list(evenIndices)
indexer=randperm(length(evenNums))
evenNums=evenNums(indexer(1:20))
NB - I make no claim concerning the validity of the 'randomness' of this method
类别
在 帮助中心 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
