a simple evoulutionary algorithm 1. the user can enter any user defined string as the evolutionary tareget up to 30 characters max

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yared Zeleke
yared Zeleke 2018-3-30
评论： yared Zeleke 2018-3-31
clc
clear
t= 'Hell world!';
numRands=length(t);
tlength=numRands;
source=t(ceil(rand(1,tlength)*numRands));
fitval = fitness(source, t);
i = 0;
while 1
i = i + 1;
m = mutate(source);
fitval_m = fitness(m, t);
if fitval_m < fitval
fitval = fitval_m;
source = m;
fprintf('%5i %5i %14s', i, fitval_m, m);
end
if fitval == 0
break
end
end
function fitval = fitness(source, t)
fitval = 0
for i = 1 : length(source)
fitval = fitval + (double(t(i)) - double(source(i))) ^ 2;
end
end
function parts = mutate(source)
parts = source;
charpos = randi(length(source)) - 1;
parts(charpos) = char(double(parts(charpos)) + (randi(3)-2));
end
  2 个评论
yared Zeleke
yared Zeleke 2018-3-30
编辑：Walter Roberson 2018-3-31
The quation is
1. The user can enter any user defined string as the evolutionary target up to 30 characters max.
2. The program should randomly generate the first ‘source’ from which to mutate.
3. The program should print-out every 100th iteration the iteration and the current mutated source and its fitness in the command window.
I tried but I have some eror I need some one to correct it to me finally the result should be the same as t

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Walter Roberson
Walter Roberson 2018-3-31
You have
charpos = randi(length(source)) - 1;
The result of that can be 0 because randi might have generated a 1. You then have
parts(charpos) = char(double(parts(charpos)) + (randi(3)-2));
but charpos can be 0 so you can be attempting to index at location 0, which is not defined.
I do not know why you are subtracting 1 at the point?

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