Error : "Assignment has more non-singleton rhs dimensions than non-singleton subscripts"

2018 3 31
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更新时间：2018 3 31
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I am getting this error: can you help me please
Assignment has more non-singleton rhs dimensions than non-singleton subscripts at
OrientationEnd(ind,1) = Table(i,j);
% Finding Orientation ...
Table=[3*pi/4 2*pi/3 pi/2 pi/3 pi/4
5*pi/6 0 0 0 pi/6
pi 0 0 0 0
-5*pi/6 0 0 0 -pi/6
-3*pi/4 -2*pi/3 -pi/2 -pi/3 -pi/4];
% Ridge Ending Orientation ...
for ind = 1:length(CentroidEndX)
Klocal = K(CentroidEndY(ind)-2:CentroidEndY(ind)+2,CentroidEndX(ind)-2:CentroidEndX(ind)+2);
Klocal(2:end-1,2:end-1) = 0;
[i,j] = find(Klocal);
OrientationEnd(ind,1) = Table(i,j);
end
Table is a 5X5 matrix

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Rik
Rik 2018-3-31
This will occur if there are more than one items in i and j.
Vishal Saini
Vishal Saini 2018-3-31
How can i resolve this error ? How can i use the first value of i and j if many values occur ?
Thanks

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Rik
Rik 2018-3-31

0 个投票

If you want to use only the first element, you can use the code below. This might still result in an error if no valid positions are found by find.
% Finding Orientation ...
Table=[3*pi/4 2*pi/3 pi/2 pi/3 pi/4
5*pi/6 0 0 0 pi/6
pi 0 0 0 0
-5*pi/6 0 0 0 -pi/6
-3*pi/4 -2*pi/3 -pi/2 -pi/3 -pi/4];
% Ridge Ending Orientation ...
for ind = 1:length(CentroidEndX)
Klocal = K(CentroidEndY(ind)-2:CentroidEndY(ind)+2,CentroidEndX(ind)-2:CentroidEndX(ind)+2);
Klocal(2:end-1,2:end-1) = 0;
[i,j] = find(Klocal);
OrientationEnd(ind,1) = Table(i(1),j(1));
end

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