Why am I getting Inf in my matrix

33 次查看（过去 30 天）
paul lestingi
paul lestingi 2018-4-1
评论： paul lestingi 2018-4-1
I am trying to divide each position element by element, and every time the denominator = 0 I want to set the result to 1 so I don't get any infinity values (for dividing by zero). When I run the code and test with find(isinf(g)) there are a ton of values that come up as infinity. Can anyone explain why?
clc
close all
x = [0 0 0; 1 2 3;0 2 4];
y = [1 2 0; 2 4 6; 2 4 5];
for u=1:3
for v=1:3
if (x(u,v) == 0)
g(u,v) = 1;
else
g(u,v) =y(u,v)/x(u,v);
end
end
end

请先登录，再回答此问题。

采纳的回答

Roger Stafford
Roger Stafford 2018-4-1
编辑：Roger Stafford 2018-4-1
It is easily possible for two finite nonzero numbers to have a quotient so large that Matlab must give 'inf' as its value. For example
x = 0.01*realmax;
y = 0.0001;
q = x/y; % <-- This will yield inf for q
I suggest you make a study of the corresponding x and y values that give rise to your inf values to see what kinds of number pairs are involved.
  1 个评论
paul lestingi
paul lestingi 2018-4-1
I'm not sure I understand. There are only two 3x3 matricies being evaluated and by looking at them none of the quotients should be near infinity.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Discrete Math 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by