How to plot function within a set of axis?
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I wrote a function code to calculate fStew. I have to plot the answer of the function within (pi,pi) but the graph is giving me blank? Here is what I wrote, fStew(theta)
ans =
-2.2737e-13
plot(fStew(theta))
I need it to be within (pi,pi) but my graph comes as blank.
采纳的回答
Birdman
2018-4-2
It is because the output of the function is scalar. Try using a specified marker inside plot:
theta=pi/6;
plot(theta,fStew(theta),'o');set(gca,'XLim',[-pi pi])
3 个评论
Birdman
2018-4-2
Luna's answer moved here:
oh. So if I'm to plot the results of fStew(theta) within pi to pi I need it to be a matrix?
Birdman
2018-4-2
Not necessarily, but if you want to see a continuous line, then yes, you need to give theta input as a vector.
Also, change and save your function as follows( elementwise oepration edit is made in your function ):
function outerr = fStew(theta)
% a function to compute f(theta)
L1 = 2;
L2 = sqrt(2);
L3 = sqrt(2);
gam = pi/2;
p1 = sqrt(5);
p2 = sqrt(5);
p3 = sqrt(5);
x1 = 4;
x2 = 0;
y2 = 4;
%parameters are defined
A2 = L3*cos(theta) - x1;
B2 = L3*sin(theta);
A3 = L2*cos(theta + gam) - x2;
B3 = L2*sin(theta + gam) - y2;
%constants are defined
N1 = B3.*(p2.^2 - p1.^2 - A2.^2 - B2.^2) - B2.*(p3.^2 - p1.^2 - A3.^2 - B3.^2);
N2 = -A3.*(p2.^2 - p1.^2 - A2.^2 - B2.^2) + A2.*(p3.^2 - p1.^2 - A3.^2 - B3.^2);
D = 2.*(A2.*B3 - B2.*A3);
%individual terms from equation 3
x = N1./D;
y = N2./D;
outerr = N1.^2 + N2.^2 - (p1.*D).^2;
%residual from equation 4
end
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