Column vector multiplied to a row vector, memory v.s. speed issue

3 次查看（过去 30 天）
Xin
Xin 2018-4-4
编辑： Stephen23 2018-4-4
Hello everyone. I have a column vector (A) that is left multiplied to a row vector (B). The result is a matrix C=A*B. What I need is the sum of C in each row, that is sum(C,2). However, both A and B are very long vector that makes C rather huge that exceeds memory. Is it possible to bypass the matrix C and get the results sum(C,2) without using a loop, which is a bit slow.
Many thanks
  6 个评论
显示 4更早的评论
Xin
Xin 2018-4-4
Depending on the data, A can be more than 1e4, and B can be more than 1e6~1e7.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Stephen23
Stephen23 2018-4-4
编辑：Stephen23 2018-4-4
Loop over A, it won't take very long as long as long as the output is preallocated. Replace this:
D1 = sum(A*B,2)
with
N = numel(A);
D2 = nan(N,1);
for k = 1:N
D2(k) = sum(A(k)*B);
end

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by