Creating a random permutation that always start with a specific value

2018 4 5
2 个回答
回答已采纳
更新时间：2018 4 5
7 次查看（30 天）

0 个投票

Dear all,
I want to create a vector of the size ten that starts with a the value one and the rest must be random. Therefore I wanted to do the following: N = [1 randperm(9)]. However, randperm only returns the values between 1 and 9 in such a case. Is there anyone who knows how this works or knows another function that could help me with my problem.
Kind regards, Thomas

请先登录，再回答此问题。

 采纳的回答

Birdman
Birdman 2018-4-5

0 个投票

It sounds like randi function can help you. First argument specifies the interval that integer values will be generated. Second and third argument specifies the number of row and column respectively.
N=[1 randi([2 9],1,8]

2 个评论
显示 无 隐藏 无

Thomas Beerten
Thomas Beerten 2018-4-5
Thanks for your answer. The problem with the answer is that it creates a vector that contains the same numbers since it creates random numbers. I wanted to use randperm such that each number is present only once in the vector. Such that you get a vector that looks the following: [1 2 3 4 5 7 6 8 9 10]. Do you may know if that is possible with the function randi?
Regards
Birdman
Birdman 2018-4-5
No that is not possible with randi. You may use randsample as follows to uniquely create numbers:
randsample(1:10,10)
But the order will be random.

请先登录，再进行评论。

类别

在 帮助中心 和 File Exchange 中查找有关 Triangular Distribution 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by