scale Image RGB

I have an image that her size is 776*608, i like to scale it and change her size to 645*463 ? Also, I have another question, how i know lineair transformation between 2 images, how to find this transformation and what should do to intensity if i find this transformation ? Any help please

2 个评论

imresize()
I know this commande but the problem i don't get the size that i predict to have in this commande . I predict to have as size 645*463 but when i use this commande i get 701*463. this is my problem

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 采纳的回答

I'm not sure I believe you that imresize() does not work. What do you notice when you run this code:
fontSize = 22;
rgbImage = uint8(randi(255, [776, 608, 3]));
subplot(1, 2, 1);
imshow(rgbImage);
title('Original Size Image', 'FontSize', fontSize);
axis on;
rgbImage2 = imresize(rgbImage, [645, 463]);
subplot(1, 2, 2);
imshow(rgbImage2);
title('Re-sized Image', 'FontSize', fontSize);
axis on;
% Enlarge figure to full screen.
set(gcf, 'units','normalized','outerposition',[0 0 1 1]);

更多回答(1 个)

Mohamed Amine
Mohamed Amine 2012-5-25

0 个投票

That's work, i forget ',' in my code. The problem now is how to match contours, i have two images i like to superpose contours and to find scale transformation. the url of two images is https://www.dropbox.com/gallery/81412928/1/Sample%20Album?h=8d9ba2
Can you help me to find how i extract transformation to superpose contours in the same position.

2 个评论

That looks more involved that I can solve in a few minutes and post here. So, good luck. You might try feature identification methods like MSER (http://en.wikipedia.org/wiki/Maximally_stable_extremal_regions), SURF, corner(), etc. SURF and MSER are in the Computer Vision Toolbox. corner() is in the Image Processing Toolbox.
My problem is not to find corresponding between two images , my problem is to superpose images with contours in the same position of the second image because when i superpose in the same position i can do segmentation easy, please i need your help it's the first step in my project. Thanks for your interesting

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