divide matrix to be sub-matrix

Question

ha ha 2018-4-12

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/394381-divide-matrix-to-be-sub-matrix

编辑： ha ha 2018-4-12

采纳的回答： Stephen23

在 MATLAB Online 中打开

A is matrix:

A=[111;222;333;444;555;666;777;888;999;1000;2000]; %total number of A is 11

I wanna divide matrix A to be "n" matrix with the equal number of each matrix :

Example (with n=4), the result is:

A1=[111;222;333];  % contain 3 element
A2=[444;555;666];  % contain 3 element
A2=[777;888;999];  % contain 3 element
A2=[1000;2000];    % contain 2 element

In this example: 11/4=2.75, so choose the number of each matrix is 3. And the number of element in the last matrix will be the remaining

And, then, store the resulted matrix in cell:

A_cell={A1, A2, A3, A4}

How to get:

A_cell={[111;222;333] ,[444;555;666], [777;888;999], [1000;2000] }

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Adam 2018-4-12

在 MATLAB Online 中打开

doc mat2cell

should help with this, although it is a function whose parameterisation always confuses me on the rare occasions I use it!

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Answer 1

Stephen23 2018-4-12

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https://ww2.mathworks.cn/matlabcentral/answers/394381-divide-matrix-to-be-sub-matrix#answer_314723

编辑：Stephen23 2018-4-12

在 MATLAB Online 中打开

Method one: mat2cell:

mat2cell(A,[3,3,3,2])

You can generate the second input like this:

>> G = 4; % pick number of groups
>> A = [111;222;333;444;555;666;777;888;999;1000;2000];
>> L = numel(A);
>> N = ceil(L/G); % max elements per group
>> V = [N*ones(1,G-1),1+mod(L-1,N)];
>> C = mat2cell(A,V);
>> C{:}
ans =
   111
   222
   333
ans =
   444
   555
   666
ans =
   777
   888
   999
ans =
   1000
   2000

Method two: accumarray:

>> V = ceil((1:L)/N);
>> C = accumarray(V(:),A,[],@(v){v});
>> C{:}
ans =
   111
   222
   333
ans =
   444
   555
   666
ans =
   777
   888
   999
ans =
   1000
   2000