How to generate function handle automatically from the cell array?

3 次查看(过去 30 天)
I have a 2x1 cell called "dx", which contains 1x3 cells:
'X * k * m' '*' '-1'
'X * k * m' '*' 'Y_XS'
I want this "dx" cell to be converted into a function. How can I do that? The generated function should look like this:
function dX = myFunc(t,X,k,m,Y_XS)
R = X(2) * k * X(1)/(X(1)+m);
dX = [-R;
Y_XS * R];
  5 个评论
Akbar
Akbar 2018-4-13
编辑:Akbar 2018-4-13
Thank You very much for helping me. I'm developing a script, at the Moment the cell Array that i have is the very first Version, it might change later.
1. No, the size is not always same.
2. Lets assume yes, for simplicity.
3. Yes
4. No
5. Please check this, I have edited the question. Basically I'm trying to create ODE function. x is a variable and others are constants which are available on workspace. I have nothing of type symbolic.
Akbar
Akbar 2018-4-13
编辑:Akbar 2018-4-13
FYI: I'm reading simulink model which simulates ODE. The Task is to get the Parameters of ODE and create a function inside matlab. So Im getting those Parameters into the cell Array called "dx". Now I want to create a function somehow.

请先登录,再进行评论。

采纳的回答

Stephen23
Stephen23 2018-4-13
编辑:Stephen23 2018-4-13
@ashadako: you have since edited your question and completely changed the function specification. This answer give the original specification: you can make the required changes yourself.
The trick is to simply arrange the strings as required, and then use str2func to get a function handle:
dx = {...
'X * k * m' '*' '-1'
'X * k * m' '*' 'Y_XS'};
isn = isnan(str2double(dx(:,3)));
tmp = dx;
tmp(:,4) = {';'};
tmp = tmp(:,4:-1:1).';
str = [tmp{:}];
var = sprintf(',%s',dx{isn,3});
str = sprintf('@(t,X,k,m,%s)[%s];',var(2:end),str(2:end));
fun = str2func(str);
This gives an anonymous function, which you can simply call with the required inputs:
>> fun(1,2,3,4,5,6)
ans =
-24
120

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Simulation Setup 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by