Regsrding for loop with array

2012 5 26
2 个回答
回答已采纳
9 次查看（30 天）

0 个投票

Hi all, A=[1;3;5; 6]; for 1 to 100 iterations, if any element in array matches with the iteration,e.g .for 1st iteration A's 1st data is matching. else it should come out from the loop. Can u suggest me any idea?
Thanks

请先登录，再回答此问题。

 采纳的回答

Wayne King
Wayne King 2012-5-26

0 个投票

for nn = 1:8
if(any(A==nn)),
disp('hi');
else
disp('bye');
end
end
Obviously, replace disp('hi') with your calculation and I've just shown this up to an index of 8.

更多回答（1 个）

0 个投票

Hi wayne, This also works!!! for lm=1:100 if (~isempty(find(A == lm))) %calcultion end end

类别

在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by