filling the cells of a column of strings

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antonet
antonet 2012-5-27
Dear all,
I have a column of string variables
'01-01-2001'
'23-11-2008'
'21-12-2008'
'18-01-2009'
and I want to fill the 1rst, 40th, 79th and so forth position of this column as follows
for j=1:hhhh*qqqq*uuu
mdata1{39*j-38,11}='01-01-2001';
end
but it is too slow. Any quicker code?
thanks

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采纳的回答

Oleg Komarov
Oleg Komarov 2012-5-27
You don't need a for loop:
mdata1(1:39:hhhh*qqqq*uuu,11) = {'01-01-2001'};

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