Replacing a value with nan

2018 4 18
2 个回答
回答已采纳
更新时间：2018 4 18
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0 个投票

Hello all. I want to replace a value that I have in accuracyC with nan if its counterpart value is nan in RTc. RTc and accuracyC are two matrices. I have written this loop but it does not work. I appreciate your help.
h=0;
for i=1:size(accuracyC,1)
for j=1:size(accuracyC,2)
if RTc(i,j)==nan
accuracyC(i,j)=NaN;
h=h+1;
end
end
end

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 采纳的回答

Star Strider
Star Strider 2018-4-18

0 个投票

Try this:

RTc = [1 2 3 NaN; 4 5 6 7; NaN 8 9 10]                      % Create Matrix
AccuracyC = randi(9, size(RTc))                             % Create Matrix

AccuracyC(isnan(RTc)) = NaN                                 % Desired Result

RTc =

       1     2     3   NaN
       4     5     6     7
     NaN     8     9    10
AccuracyC =

       7     1     6     6
       8     3     9     3
       1     8     2     1
AccuracyC =

       7     1     6   NaN
       8     3     9     3
     NaN     8     2     1

更多回答（1 个）

Dennis
Dennis 2018-4-18

0 个投票

I read about this lately, NaN never equals NaN (some IEEE stuff).

But you can use isnan instead.

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