0 个投票

Lets say I have a time T1 = '2018-03-14 16:30:54' and another T2 = '2018-03-14 16:40:54' How can I find the total duration of the interval, as well as a "midpoint" in between said interval? My goal is to add an NaN entry every time there is a time gap greater than 10 minutes.
For example; '2018-03-14 16:30:54' '2018-03-14 16:40:54' %NaN entry would be added here '2018-03-14 17:20:15' '2018-03-14 17:30:15'
The purpose of adding this entry would be to remove discontinuity in graphs.

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the cyclist
the cyclist 2018-4-18
编辑：the cyclist 2018-4-18

1 个投票

T1 = datetime('2018-03-14 16:30:54');
T2 = datetime('2018-03-14 16:40:54');

dT = T2 - T1;

T_mid = T1 + dT/2;

3 个评论
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Miguel Herrera
Miguel Herrera 2018-4-18
Thank you. Follow up question, what can I do to make the following code work if dT > 00:12:00 disp('TRUE') else disp('FALSE') end
I keep getting TRUE even though the answer should be false. Does this have to do with the fact that dT is a duration and should also be compared to another duration using that if statement?
the cyclist
the cyclist 2018-4-19
编辑：the cyclist 2018-4-19
There might be a better way, but ...
dT > duration('12:00','InputFormat','mm:ss')
Peter Perkins
Peter Perkins 2018-4-19
dT > hours(12)
The cyclists code will work in R2018a or later, but in any case using hours seems much more readable to me.

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更多回答（2 个）

Peter Perkins
Peter Perkins 2018-4-19

1 个投票

>> d = datetime(2018,3,14,16,[30 40],54)
d = 
  1×2 datetime array
   14-Mar-2018 16:30:54   14-Mar-2018 16:40:54
>> mean(d)
ans = 
  datetime
   14-Mar-2018 16:35:54
>> diff(d)
ans = 
  duration
   00:10:00
Steven Brossi
Steven Brossi 2022-8-8
Ran in:

0 个投票

Ran in:
How about
T1 = datetime('2018-03-14 16:30:54')
T1 = datetime
14-Mar-2018 16:30:54
T2 = datetime('2018-03-14 16:40:54')
T2 = datetime
14-Mar-2018 16:40:54
T_mid = mean([T1, T2])
T_mid = datetime
14-Mar-2018 16:35:54

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