this is my equation using matlab , i can't get it manually.

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maatoug ayoub 2018-4-19

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https://ww2.mathworks.cn/matlabcentral/answers/396056-this-is-my-equation-using-matlab-i-can-t-get-it-manually

评论： maatoug ayoub 2018-4-19

采纳的回答： njj1

在 MATLAB Online 中打开

dmat = reshape(sqrt(sum((xy(a,:)-xy(a',:)).^2,2)),N,N);

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maatoug ayoub 2018-4-19

编辑：Stephen23 2018-4-19

在 MATLAB Online 中打开

for k = nargin:nargs-1
    switch k
        case 0
            xy = 10*rand(20,2);
        case 1
            N = size(xy,1);
            a = meshgrid(1:N);
            dmat = reshape(sqrt(sum((xy(a,:)-xy(a',:)).^2,2)),N,N);
          case 2
              salesmen = 4;
          case 3
              min_tour = 2;
          case 4
              pop_size = 80;
          case 5
              num_iter = 5e3;
          case 6
              show_prog = 1;
          case 7
              show_res = 1;
          otherwise
      end

maatoug ayoub 2018-4-19

this is a part of the script

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采纳的回答

njj1 2018-4-19

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编辑：njj1 2018-4-19

This looks like it's the distance from each (x,y) pair to every other (x,y) pair.

A_{i,j} = \sqrt{(x_i - x_j)^2}, where x = (x,y)

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njj1 2018-4-19

Yes, it is, but they do it in a clever, vectorized way, where they do not have any for loops to cycle through each i,j.

maatoug ayoub 2018-4-19

thank you my friend now i untrestand it

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