In a matrix how to replace zero by NaN.?

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Safi ullah
Safi ullah 2018-4-19
评论： 拓郎 下山 2021-5-3
Hi every one, I have a matrix A=1×180. All values of matrix A are either zeros or negative numbers. I need to replace all the zeros by NaN, noted that zeros are also randomly distributed in matrix A. I have tried for loop but do not get the desired result. Any guidance will be appreciated thanks.
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拓郎 下山
拓郎 下山 2021-5-3
I have the same problem.
I change 0 value to NaN value in nifti file of int16.
I try "V(V==0) = NaN;"
But, it doesn't work. Could you give me the answer?
Thank you for reading.

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njj1
njj1 2018-4-19

Try this:

A(A==0) = NaN;
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laith awwad
laith awwad 2021-4-21
HOW TO NAME THE VARIABLE BECAUSE IF I RIGHT FOR EXAMPLE e = A(A==0) = NaN; GIVES ME AN ERROR
Steven Lord
Steven Lord 2021-4-21
Ran in:
If you want to keep the original array around, make a copy of it then replace the values in that copy.
A = randperm(10)
A = 1×10
9 5 7 3 8 10 2 1 4 6
B = A;
B(B > 7) = NaN
B = 1×10
NaN 5 7 3 NaN NaN 2 1 4 6
[A; B] % Use both the original vector (A) and the modified one (B)
ans = 2×10
9 5 7 3 8 10 2 1 4 6 NaN 5 7 3 NaN NaN 2 1 4 6

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