am trying to get the non zero minimum values from all the rows. Am getting the correct minimum values but the indices for minimum values for the first and second rows are wrong. Suggest me where I am wrong

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akash sonnad 2018-4-23

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评论： KSSV 2018-4-23

C=[0,10,8,9,7;10,0,10,5,6;8,10,0,8,9;9,5,8,0,6;7,6,9,6,0]; j=5; for n=1:j e=C(n,:); [M(n),I(n)]=min(e(e>0)); end disp(M); disp(I);

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Answer 1

KSSV 2018-4-23

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在 MATLAB Online 中打开

matC=[0,10,8,9,7;10,0,10,5,6;8,10,0,8,9;9,5,8,0,6;7,6,9,6,0];
matC(matC==0) = NaN ;
j=5;
for n=1:j
    e=matC(n,:);
    [M(n),I(n)]=min(e);
end
disp(M);
disp(I);

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akash sonnad 2018-4-23

It's working, Thank you. Can you please elaborate on the code matC (matC == 0) = NaN;

KSSV 2018-4-23

You are picking up minimum value greater then 0.....so that line replaces all zeros in the matrix with NaN. e(e>0) picks only non-zero values..and gives minimum, this will give different index when compared to original matrix.

Note: You need not to use loops for this...you can striagh away use min on matrix.

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Answer 2

Stephen23 2018-4-23

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编辑：Stephen23 2018-4-23

在 MATLAB Online 中打开

There is no point in wasting your time writing ugly for loops, because the MATLAB function min does exactly what you want already, much more efficiently than anything you could write using a loop:

>> C = [0,10,8,9,7;10,0,10,5,6;8,10,0,8,9;9,5,8,0,6;7,6,9,6,0];
>> C(C==0) = NaN; % convert zeros to NaN
>> [val,idx] = min(C,[],1)
val =
   7   5   8   5   6
idx =
   5   4   1   2   2

And that is all. MATLAB is a neat high-level language, so it should not be written as if it was an ugly low-level language like C++.