Use of loops to print the contents of a cell array with varying number of rows

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Bob Sherland
Bob Sherland 2018-4-25
编辑： Stephen23 2018-4-25
So I have a cell array called cell array called system in which I have
system={'file one' 'author one' [100]; 'file two' 'author two' [100]; 'file three' 'author three; [100]}
And I am wondering what process I can use to get an output of
Title: file one
Author: author one
No_pages: 100
Title: file two
Author: author two
No_pages: 100
Title: file three
Author: author three
No_pages: 100
And I need to process to work a cell array with more rows, how exactly should I structure the loop to go through and print the display as shown above?

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回答（2 个）

Stephen23
Stephen23 2018-4-25
编辑：Stephen23 2018-4-25
No loops are required, just transpose the cell array and use a comma-separated list:
>> C = {'file one','author one',100;'file two','author two',100;'file three','author three',100};
>> fmt = 'Title: %s\nAuthor: %s\nNo. pages: %d\n\n';
>> tmp = C.';
>> fprintf(fmt,tmp{:})
Title: file one
Author: author one
No. pages: 100
Title: file two
Author: author two
No. pages: 100
Title: file three
Author: author three
No. pages: 100
Why make things more complicated than they need to be?
Benjamin Großmann
Benjamin Großmann 2018-4-25
Use a struct array instead of cell array and then disp inside an arrayfun:
clearvars
close all
clc
system(1).Title = 'file one';
system(1).Author = 'author one';
system(1).No_pages = 100;
system(2).Title = 'file two';
system(2).Author = 'author two';
system(2).No_pages = 100;
system(3).Title = 'file three';
system(3).Author = 'author three';
system(3).No_pages = 100;
arrayfun(@(x) disp(system(x)),[1:numel(system)])
You can also convert your existing cell to stuct array using cell2struct.

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