I want to reduce accuracy and precision to 3 digits.

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meh hadi
meh hadi 2018-4-25
评论： Walter Roberson 2018-5-2
for example I want to a=2.18+0.139; with 3 digits answer must be 2.31. is any way to do this?
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Tom Wenk
Tom Wenk 2018-4-25
编辑：Tom Wenk 2018-4-26
Then I think you have to use the symbolic toolbox like Walter Robinson stated.
But why do you want to change 2.319 to 2.31 rather than 2.32? If you use this value for further calculations you should round in my opinion..

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回答（3 个）

Praveen Iyyappan Valsala
I don't know any inbulit function which can do that. But, you can try something like below
trun=@(num,Ndigits)floor(a*10^Ndigits)/10^Ndigits;
trun_a=trun(a,2);
Walter Roberson
Walter Roberson 2018-4-25
No, there is no built-in way.
You can use the symbolic toolbox with digits set to 3, but that will round rather than truncate.
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Stephen23
Stephen23 2018-4-26
Note that setting the digits does not mean that calculations will be performed with exactly that precision, because calculations may use guard digits.

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Tom Wenk
Tom Wenk 2018-4-25
Like Walter Roberson stated, I think you have to use the symbolic toolbox for that.
Maybe this function from the toolbox can help you: https://de.mathworks.com/help/symbolic/digits.html
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Walter Roberson
Walter Roberson 2018-5-2
For addition: multiply the original values by 100, take floor() or fix(). Do the addition. Divide the result by 100.

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