Stop the for loop

Question

Adrian 2012-5-29

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/39770-stop-the-for-loop

I want to stop a loop when the the modulo 26 of the determinant times a 'number', then use such 'number' to multiply the inverse of a matrix. The code is:

clc, clear;
A=input('Symmetric matrix: ');
format rat;
d=det(A)
Minv=inv(A);
M1=(Minv*d);
for i=1:100
  j=mod(d*i, 26);
  x=i;
  if j==1, break, end
end
x
Z=round(mod((M1*x), 26))

However I can't make the for loop to stop when the value of 'j' becomes 1 and use the value of 'x' to multiply the matrix; every time the value of x is the final value of 'i', in this case 100.

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Oleg Komarov 2012-5-29

Why do you expect the modulus of d*i should ever be 1?

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Answer 1

Geoff 2012-5-29

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/39770-stop-the-for-loop#answer_49415

在 MATLAB Online 中打开

Time for the most basic of debugging practises...

After you calculate j, put in the following line of code:

disp(j);

Now, run your loop.

I'm willing to bet that j is either always even (because d is even), or is a sufficiently fractional non-integer.

When you work out what's happening and fix it, then consider the following. From a 'performance' perspective (well, really it's about not doing unnecessary things), just save the value into x once:

x = [];
for i = 1:100
  if mod(d*i,26) == 1
    x = i;
    break;
  end
end
if isempty(x)
  disp('Not found');
end

Doesn't really matter here, but it's worth getting into the habit of recognising some repeated calculations as being pointless. Call it "eco-coding". =)

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Geoff 2012-5-29

Then it's probably not _exactly_ 1. Try this:

fprintf( 'i=%d : j=%.30f\n', i, j);

You might need to test with something like:

if abs(j-1) < eps(10)

Adrian 2012-5-29

That was it! The only thing I had to finish so my encryption/decryption program was finished. I am just starting to learn matlab and your help is really appreciated.

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