Increase determine step size

Question

0 个投票

Hello I want to have this steps (1,2,4,6,8).

How can I do it to be in the form of, for example:

n=5 
n=1:2:((2*n)-2)

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

Answer 1

Walter Roberson 2018-4-27

0 个投票

t = 1:5; steps = 3+(-53/12+(71/24+(-7/12+(1/24)*t).*t).*t).*t

I would suggest that you reconsider your task. It would, for example, have been much easier as

t = 1:5; steps = [1, (t(2:end)-1)*2]

Kostas Tsakos 2018-4-27

I want the code to be x=1:times 2:8 (so i get 1,2,4,6,8)

Walter Roberson 2018-4-27

You cannot get that.

You can use (t-1)*2 + (t==1) or other ways of making an exception for the first value, but the 1 entry cannot be handled with a plain increment.

Now, if you had wanted [1, 2, 4, 8] without the 6 then that would have been easy: t = 1:4; 2.^(t-1)

Answer 2

Image Analyst 2022-8-9

0 个投票

Try this:

n = 5;
n = [1,2:2:((2*n)-2)]
n = 1×5
     1     2     4     6     8