Info

此问题已关闭。 请重新打开它进行编辑或回答。

Hi, can you help me!!! I 've got a problem when i went to calculate this matrix:

2 次查看（过去 30 天）
yousra yahia
yousra yahia 2018-5-1
关闭： MATLAB Answer Bot 2021-8-20
A= [Aa 0;-Af*Ca Af]
With
Aa=[-0.01320 0 0 9.8100 0 0 0 0;-0.08560 -0.9903 -241.7000 0 21.7500 0.9504 18.0800 -0.00073;-0.00017 0.0159 -0.9883 0 -0.4850 -0.0323 -3.3200 -0.10450;0 0 1 0 0 0 0 0;0 0 0 0 0 1 0 0;0.08420 0.8897 -3.0300 0 -164.6000 -4.2050 -28.0500 -0.59690;0 0 0 0 0 0 0 1;-0.02920 -0.1723 -5.0970 0 -2.8540 -0.4456 -430.5000 -2.15500];
Af=diag([-10 -10]);
  5 个评论
显示 3更早的评论
yousra yahia
yousra yahia 2018-5-1
编辑：Walter Roberson 2018-5-1
Af=diag([-10 -10]);
Ca=[-0.05540 -0.6511 5.1620 0 112.2000 3.0360 152.9000 1.1390;-0.00804 -0.0850 0.2943 0 -2.9510 -0.0590 -26.5500 -0.1560];
Aa=[-0.01320 0 0 9.8100 0 0 0 0;-0.08560 -0.9903 -241.7000 0 21.7500 0.9504 18.0800 -0.00073;-0.00017 0.0159 -0.9883 0 -0.4850 -0.0323 -3.3200 -0.10450;0 0 1 0 0 0 0 0;0 0 0 0 0 1 0 0;0.08420 0.8897 -3.0300 0 -164.6000 -4.2050 -28.0500 -0.59690;0 0 0 0 0 0 0 1;-0.02920 -0.1723 -5.0970 0 -2.8540 -0.4456 -430.5000 -2.15500];
A=[Aa 0;-Af.*Ca Af];
Error using horzcat
Dimensions of matrices being concatenated are not consistent.
Error in Matrice (line 4)
A=[Aa 0;-Af.*Ca Af];

此问题已关闭。

回答（1 个）

James Tursa
James Tursa 2018-5-1
编辑：James Tursa 2018-5-1
You need to tell MATLAB how many 0's are being concatenated in the upper right corner. E.g.,
A = [Aa zeros(size(Aa,1),size(Af,2));-Af*Ca Af];
  3 个评论
显示 1更早的评论
the cyclist
the cyclist 2018-5-1
编辑：the cyclist 2018-5-1
This code, which is exactly what you posted (with a bit of reformatting), and James' correction, worked for me.
Af=diag([-10 -10]);
Ca=[-0.05540 -0.6511 5.1620 0 112.2000 3.0360 152.9000 1.1390;
-0.00804 -0.0850 0.2943 0 -2.9510 -0.0590 -26.5500 -0.1560];
Aa=[-0.01320 0 0 9.8100 0 0 0 0;
-0.08560 -0.9903 -241.7000 0 21.7500 0.9504 18.0800 -0.00073;
-0.00017 0.0159 -0.9883 0 -0.4850 -0.0323 -3.3200 -0.10450;
0 0 1 0 0 0 0 0;
0 0 0 0 0 1 0 0;
0.08420 0.8897 -3.0300 0 -164.6000 -4.2050 -28.0500 -0.59690;
0 0 0 0 0 0 0 1;
-0.02920 -0.1723 -5.0970 0 -2.8540 -0.4456 -430.5000 -2.15500];
A = [Aa zeros(size(Aa,1),size(Af,2));-Af*Ca Af];
Note that John changed
-Af.*Ca
to
-Af*Ca
to make it a matrix multiplication. Your code, which would do element-by-element multiplication would fail because you cannot do that between a 2x2 and a 2x8. Whether that type of multiplication is what you need is up to you to determine.
yousra yahia
yousra yahia 2018-5-2
Thank you, i got the result but i had an other problem :
Af=diag([-10 -10]) Da=[4.3970 33.4300; -0.4182 -1.1780] Ba=[0 0;6.8060 9.2750; -1.7700 -0.7986; 0 0;0 0; 6.1130 -42.0300; 0 0; -20.2700 -13.2900] B=[Ba -Af*Da]
>> Af=diag([-10 -10]) Da=[4.3970 33.4300; -0.4182 -1.1780] Ba=[0 0;6.8060 9.2750; -1.7700 -0.7986; 0 0;0 0; 6.1130 -42.0300; 0 0; -20.2700 -13.2900] B=[Ba -Af*Da]
Af =
-10 0
0 -10
Da =
4.3970 33.4300
-0.4182 -1.1780
Ba =
0 0
6.8060 9.2750
-1.7700 -0.7986
0 0
0 0
6.1130 -42.0300
0 0
-20.2700 -13.2900
Error using horzcat Dimensions of matrices being concatenated are not consistent.

此问题已关闭。

标签

尚未输入任何标签。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by