Hi, can you help me!!! I 've got a problem when i went to calculate this matrix:

Question

yousra yahia 2018-5-1

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关闭： MATLAB Answer Bot 2021-8-20

A= [Aa 0;-Af*Ca Af]

With

Aa=[-0.01320 0 0 9.8100 0 0 0 0;-0.08560 -0.9903 -241.7000 0 21.7500 0.9504 18.0800 -0.00073;-0.00017 0.0159 -0.9883 0 -0.4850 -0.0323 -3.3200 -0.10450;0 0 1 0 0 0 0 0;0 0 0 0 0 1 0 0;0.08420 0.8897 -3.0300 0 -164.6000 -4.2050 -28.0500 -0.59690;0 0 0 0 0 0 0 1;-0.02920 -0.1723 -5.0970 0 -2.8540 -0.4456 -430.5000 -2.15500];
Af=diag([-10 -10]);

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yousra yahia 2018-5-1

编辑：Walter Roberson 2018-5-1

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Af=diag([-10 -10]);
Ca=[-0.05540 -0.6511 5.1620 0 112.2000 3.0360 152.9000 1.1390;-0.00804 -0.0850 0.2943 0 -2.9510 -0.0590 -26.5500 -0.1560];
Aa=[-0.01320 0 0 9.8100 0 0 0 0;-0.08560 -0.9903 -241.7000 0 21.7500 0.9504 18.0800 -0.00073;-0.00017 0.0159 -0.9883 0 -0.4850 -0.0323 -3.3200 -0.10450;0 0 1 0 0 0 0 0;0 0 0 0 0 1 0 0;0.08420 0.8897 -3.0300 0 -164.6000 -4.2050 -28.0500 -0.59690;0 0 0 0 0 0 0 1;-0.02920 -0.1723 -5.0970 0 -2.8540 -0.4456 -430.5000 -2.15500];
A=[Aa 0;-Af.*Ca Af];
Error using horzcat
Dimensions of matrices being concatenated are not consistent.
Error in Matrice (line 4)
A=[Aa 0;-Af.*Ca Af];

Walter Roberson 2018-5-1

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Answer 1

James Tursa 2018-5-1

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编辑：James Tursa 2018-5-1

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You need to tell MATLAB how many 0's are being concatenated in the upper right corner. E.g.,

A = [Aa zeros(size(Aa,1),size(Af,2));-Af*Ca Af];

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the cyclist 2018-5-1

编辑：the cyclist 2018-5-1

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This code, which is exactly what you posted (with a bit of reformatting), and James' correction, worked for me.

Af=diag([-10 -10]);
Ca=[-0.05540 -0.6511 5.1620 0 112.2000 3.0360 152.9000 1.1390;
    -0.00804 -0.0850 0.2943 0 -2.9510 -0.0590 -26.5500 -0.1560];
Aa=[-0.01320 0 0 9.8100 0 0 0 0;
    -0.08560 -0.9903 -241.7000 0 21.7500 0.9504 18.0800 -0.00073;
    -0.00017 0.0159 -0.9883 0 -0.4850 -0.0323 -3.3200 -0.10450;
    0 0 1 0 0 0 0 0;
    0 0 0 0 0 1 0 0;
    0.08420 0.8897 -3.0300 0 -164.6000 -4.2050 -28.0500 -0.59690;
    0 0 0 0 0 0 0 1;
    -0.02920 -0.1723 -5.0970 0 -2.8540 -0.4456 -430.5000 -2.15500];
A = [Aa  zeros(size(Aa,1),size(Af,2));-Af*Ca  Af];

Note that John changed

-Af.*Ca

to

-Af*Ca

to make it a matrix multiplication. Your code, which would do element-by-element multiplication would fail because you cannot do that between a 2x2 and a 2x8. Whether that type of multiplication is what you need is up to you to determine.

yousra yahia 2018-5-2

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Thank you, i got the result but i had an other problem :

Af=diag([-10 -10]) Da=[4.3970 33.4300; -0.4182 -1.1780] Ba=[0 0;6.8060 9.2750; -1.7700 -0.7986; 0 0;0 0; 6.1130 -42.0300; 0 0; -20.2700 -13.2900] B=[Ba -Af*Da]

>> Af=diag([-10 -10]) Da=[4.3970 33.4300; -0.4182 -1.1780] Ba=[0 0;6.8060 9.2750; -1.7700 -0.7986; 0 0;0 0; 6.1130 -42.0300; 0 0; -20.2700 -13.2900] B=[Ba -Af*Da]

Af =

   -10     0
     0   -10

Da =

    4.3970   33.4300
   -0.4182   -1.1780

Ba =

         0         0
    6.8060    9.2750
   -1.7700   -0.7986
         0         0
         0         0
    6.1130  -42.0300
         0         0
  -20.2700  -13.2900

Error using horzcat Dimensions of matrices being concatenated are not consistent.