Extracting every n number of column from matrix matlab

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Aybars
Aybars 2018-5-3
评论： Ameer Hamza 2018-8-16
0 down vote favorite I need to extract every n number of column from my matrix. Please note that not every nth column. For example I have a matrix:
A =
1 23 34 53 67 45 67 45
12 34 45 56 67 87 98 12
1 2 3 45 56 76 87 56
And I want to extract each 3 column, so my data should be like:
X =
1 23 34 67 45 67
12 34 45 67 87 98
1 2 3 56 76 87
So I would skip 4th column then 8th column and so on. I know how to extract every nth column and row but I couldn't figure it out what I need. Appreciated for your help

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采纳的回答

Ameer Hamza
Ameer Hamza 2018-5-3
编辑：Ameer Hamza 2018-5-3
Here is a general solution to your problem in which you can specify how many columns to keep and how many to delete
colToKeep = 2;
colToDelete = 3;
ColIndex = mod( 0:size(A,2)-1, colToKeep+colToDelete ) < colToKeep;
A(:, ~ColIndex) = [];
Use colToKeep and colToDelete to specify the values.
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Ameer Hamza
Ameer Hamza 2018-8-16
Just take the transpose of the matrix and apply the same method. At the end take the transpose again to get the correct matrix.

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更多回答（2 个）

Yuvaraj Venkataswamy
编辑：Yuvaraj Venkataswamy 2018-5-3
Answer is below where A is a your matrix.
if true
n=4;
A =[1 23 34 53 67 45 67 45
12 34 45 56 67 87 98 12
1 2 3 45 56 76 87 56]
A(:,n:n:end) =[]
end
  1 个评论
Aybars
Aybars 2018-5-3
Hi, Thank you very much for your answer. It is correct. But in that case, how can I adjust the number of column that I want to skip ? For example I would like to take first 2 columns, then skip 3 columns then take 2 columns again.

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Guillaume
Guillaume 2018-5-3
X = A;
X(:, 4:4:end) = [];
  1 个评论
Aybars
Aybars 2018-5-3
Hi, Thank you very much for your answer. It is correct. But in that case, how can I adjust the number of column that I want to skip ? For example I would like to take first 2 columns, then skip 3 columns then take 2 columns again.

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