Why am I getting a parse error at the logical operator &&?

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Kristen O'Mara 2018-5-3

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评论： Kristen O'Mara 2018-5-3

For some reason I am getting a parse error at && which will not allow my code to run.

 function [nucleotides] = BMEactivity(m1, m2)
 for i = 1:m1(end)
 if m1(i) >= && m2(i) >= 0
    nucleotides(i) = 'A';
 elseif m1(i) < 0 && m2(i) >= 0
    nucleotides(i) = 'C';
 elseif m1(i) >= 0 && m2(i) < 0
    nucleotides = 'G';
 elseif m1(i) < 0 && m2(i) < 0
    nucleotides(i) = 'T';
 else 
 end
 end
 end

Also, I'm not quite sure if this is the correct syntax in the for loop for indexing to the last element of the array. It would be ideal if there was one expression that let me index to the end of m1 and m2 simultaneously.

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Answer 1

Star Strider 2018-5-3

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在 MATLAB Online 中打开

You’re not incrementing the loop.

Try this:

m1 = randi([-1 1], 20, 1);                              % Create Data
m2 = randi([-1 1], 20, 1);                              % Create Data
for i = 1:numel(m1)
      if m1(i) >= 0 && m2(i) >= 0
          nucleotides(i) = 'A';
      elseif m1(i) < 0 && m2(i) >= 0
          nucleotides(i) = 'C';
      elseif m1(i) >= 0 && m2(i) < 0
          nucleotides(i) = 'G';
      elseif m1(i) < 0 && m2(i) < 0
          nucleotides(i) = 'T';
      end
  end