trying to model points inside a sphere
14 次查看(过去 30 天)
显示 更早的评论
if true
clear
clear all
r=randn(0,1);
theta=randn(0,1)*(pi);
phi=randn(0,1)*(2*pi);
for N=1:20
hold on
x=r(N).*sin(theta(N)).*cos(phi(N));
y=r(N).*sin(theta(N)).*sin(phi(N));
z=r(N).*cos(theta(N));
end
hold off
drawnow
% code
end
I am trying to model a bunch of points inside a sphere, I put the spherical cooridinates into cartesian, but cannot get it to plot, any help would be appreciated.
5 个评论
jonas
2018-5-4
Great! I will post an answer for future reference, if anyone else wants to model a sphere with random points
回答(1 个)
jonas
2018-5-4
This will generate a sphere with random points inside of it (code adapted from the original question):
if true
clear
clear all
n=20;
r=rand(n,1);
theta=rand(n,1)*pi;
phi=rand(n,1)*(2*pi);
x=r.*sin(theta).*cos(phi);
y=r.*sin(theta).*sin(phi);
z=r.*cos(theta);
sphere;
hold on
scatter3(x,y,z)
hold off
% code
end
ha=get(gca,'children')
set(ha(2),'FaceColor',[0 0 0],'FaceAlpha',0.1,'EdgeAlpha',0.2)
1 个评论
David Goodmanson
2018-5-5
Hi Jonas / Devin,
This code is pretty good, except if you try it for something like n = 2000 you will see a cluster of points in the middle of the sphere and also along the z axis. It's more usual to be looking for a uniform density of points in the sphere, which would be
r = rand(n,1).^(1/3);
costheta = 2*rand(n,1)-1;
sintheta = sqrt(1-costheta.^2);
phi=rand(n,1)*(2*pi);
x=r.*sintheta.*cos(phi);
y=r.*sintheta.*sin(phi);
z=r.*costheta;
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Surface and Mesh Plots 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!