I have a 1x50 cell array with a 780x6 table in each cell. I can access the cells but i would like to convert the different tables into matrices and give them a distinctive name but the loop gives me an error every time

Question

Robin Häsler 2018-5-3

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/398935-i-have-a-1x50-cell-array-with-a-780x6-table-in-each-cell-i-can-access-the-cells-but-i-would-like-to

评论： Stephen23 2018-5-4

 Simulations =
1×50 cell array
%now I tried to build a loop which converts every cell into a matrix and names the matrices
for i = 1:50
a(i) = table2array(Simulations{1,i})
end
%this gives me the following error-> Unable to perform assignment because the left and right sides have a different number of elements.

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Stephen23 2018-5-4

"i would like to convert the different tables into matrices and give them a distinctive name"

Do NOT do that. Dynamically creating/accessing variable names is how beginners force themselves into writing slow, complex, buggy code that is hard to debug. Just use a cell array with indexing. Indexing is neat, easy to debug, and very efficient. Read this to know more:

https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

sloppydisk 2018-5-3

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/398935-i-have-a-1x50-cell-array-with-a-780x6-table-in-each-cell-i-can-access-the-cells-but-i-would-like-to#answer_318584

在 MATLAB Online 中打开

You cannot store matrices inside matrices, you can however leave them inside the cell and convert them there using table2array:

% construct tables in cell
a = cell(1, 50);
b = rand(780, 6);
a(:) = {table(b(:, 1), b(:, 2), b(:, 3), b(:, 4), b(:, 5), b(:, 6))};
class(a{1})
% convert data to doubles in cell
a(:) = {table2array(a{:})};
class(a{1})

Note that a(1) gives a 1x1 cell, while a{1} gives the contents of that cell.