matrix of circulating vectors without loop
显示 更早的评论
hi all , I want to built a matrix of circulating vectors without using loops
for example
input:
1 2 3 4
4 5 6 7
3 8 4 6
output :
1 2 3 4
4 1 2 3
3 4 1 2
2 3 4 1
4 5 6 7
7 4 5 6
6 7 4 5
5 6 7 4
3 8 4 6
6 3 8 4
4 6 3 8
8 4 6 3
I use the code
v =[1,2,3,4;4,5,6,7;3,8,4,6]
%notice the length of each vector in v is equal
len_rows=length(v(:,1));
len_cols=length(v(1,:));
mat_shifted=zeros(len_rows*len_cols,len_cols);
j=1;
for i=1:len_rows
vec=v(i,:);
mat=toeplitz([vec(1) fliplr(vec(2:end))], vec)
mat_shifted(j:j+len_cols-1,:)=mat
j=j+len_cols;
end
is there a smart way to do it without using loops , thanks in advance
采纳的回答
更多回答(2 个)
I think your concept is quite reasonable You could simplify the code a bit by using a cell array for the output, rather than keeping track of the rows:
M = [1,2,3,4;4,5,6,7;3,8,4,6];
N = size(M,1);
C = cell(N,1);
for k = 1:N
V = M(k,:);
C{k} = toeplitz([V(1),V(end:-1:2)],V);
end
Z = vertcat(C{:})
Carlos Sanchis
2018-5-4
Still with a for loop, but somewhat more readable...
input = [1 2 3 4; ...
4 5 6 7; ...
3 8 4 6];
[m, n] = size(input);
output = zeros(m * n, n);
for s = 0:n-1
output((0:m-1) * n + s + 1, :) = circshift(input, s, 2);
end
expected = [1 2 3 4; 4 1 2 3; 3 4 1 2; 2 3 4 1; ...
4 5 6 7; 7 4 5 6; 6 7 4 5; 5 6 7 4; ...
3 8 4 6; 6 3 8 4; 4 6 3 8; 8 4 6 3];
assert(isequal(output, expected));
类别
在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!