I am trying to get a 3*3 diagnol matrix by using the following code. But the resultant matrix dimensions exceed 3*3 matrix.

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Ameer Hamza
Ameer Hamza 2018-5-6
评论： Ameer Hamza 2018-5-6
theta = 0:pi:2*pi;
a = cos(theta)+sin(theta);
A = ismatrix([[a,0,0],[0,a,0],[0,0,a]]);
a = cos(theta)+sin(theta);
A = ismatrix([[a,0,0],[0,a,0],[0,0,a]]);
B = [a 0 0;0 a 0;0 0 a];
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Ameer Hamza
Ameer Hamza 2018-5-6
Thanks for the response, what i want to do is to get set of numbers in the matrix while keeping size of the matrix same. for example: a = 0:2*pi b = cos(a)+sin(a) c = [b 0 0;0 b 0;0 0 b] I can use diag to get the response keeping the matrix dimension same but it only gives me the final values. for theta = 0:2*pi a = cos(theta)+sin(theta); c = [a 0 0;0 a 0;0 0 a] end doing so gives me the result but i get number of matrices with each values of theta but the workspace stores just the final matrix.

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Ameer Hamza
Ameer Hamza 2018-5-6
编辑：Ameer Hamza 2018-5-6
If you want the element of a to be the diagonal of B, you need something like this
theta = 0:pi:2*pi;
a = cos(theta)+sin(theta);
B = diag(a);
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Ameer Hamza
Ameer Hamza 2018-5-6
Thank you. My problem is that Matlab dont store all the values of matrix a , it store only the final value. I tried the method in this video https://blogs.mathworks.com/videos/2007/08/20/matlab-basics-video/ but it increase the dimension of the matrix. I need only (3*3) matrix.
Ameer Hamza
Ameer Hamza 2018-5-6
In that video, for loop is used. In my code there is not for loop and MATLAB does store all the values of a. Have you tried running the code? The following code gives a vector (containing all values of a)
theta = 0:pi:2*pi;
a = cos(theta)+sin(theta);
disp(theta);
ans =
0 3.1416 6.2832
disp(a);
ans =
1 -1 1
You still did not explain, what do you want in MATRIX?

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