spell cheaker stuck in loop

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Ive got a simple enough problem code has to make sure user input is correct but Ive made a very ugly while loop and its not working at all probably needs to be completely redone, any tips are appreciated
if true
InputString = input('Input:', 's');
lenghtInput = length(InputString);
test = 'UuGgCcAa';
i = 1;
j = 1;
c = 1;
correctInput = false;
while correctInput ~= true
if InputString(i) ~= test(j) || j == lenghtInput
++j;
++c;
display(i)
if c == 3
c = 0;
i = i + 1;
end
end
correctInput = true;
end
%code
%it needs to check the only characters used are in the test variable
  4 个评论
riley collins
riley collins 2018-5-7
编辑:riley collins 2018-5-7
i should have explained better, the code can contain any pattern or sequence but i need to make sure it only contains "ugca" and their upper case counter parts and ++j isnt syntax uhg im getting languages mixed up again i think....
KSSV
KSSV 2018-5-7
If you want to compare strings have a look on strcmp and strcmpi.

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采纳的回答

Walter Roberson
Walter Roberson 2018-5-7
tf = ismember(InputString, 'UuGgCcAa');
correctInput = all(tf);
  4 个评论
Walter Roberson
Walter Roberson 2018-5-7
tf is an arbitrary variable name for this purpose. It could have been written as
are_individual_letters_correct = ismember(InputString, 'UuGgCcAa');
correctInput = all(are_individual_letters_correct);
The letters that are wrong would be
bad_letters = InputString(~are_individual_letters_correct);
ismember() checks each vector element in InputString against every element of 'UuGgCcAa' and returns true in the places that match and false in the places that do not match. If everything comes out as true then the entire string is valid.

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