size

Question

skyimager 2012-5-31

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/39994-size

VAR_START =

     9    12    14    17    24    31    34    37    40    43    46    49    52    55    58    61    64

>> NVAR = size(VAR_START)

NVAR =

1 17

What is the function of 'size' here???? why is it giving 1 17...???? I am srry bt i cannot understand!!!

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Oleg Komarov 2012-5-31

For future reference whenver you don't know wha rt a function does, doc size, or use F1

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Image Analyst 2012-5-31

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/39994-size#answer_49622

That's just the way size works. It's kind of like they expect size() to be used with arrays that are 2 dimensions or more. Get used to it. It says your "array" is 1 row by 17 columns. If you want just the "17" and not the "1" and you know in advance that you have a 1 dimensional array, then use length() function instead of the size() function. The length() function will give you 17 - a single number - without it being a 2 element result with the unhelpful "1" as the first element. length() gives you the length of the longest dimension, which is kind of confusing, so I use length() for 1D arrays (and only for 1D arrays), and size() for 2D or higher dimensional arrays.