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Problem Expanding a Matrix

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Charles Martineau
Charles Martineau 2012-5-31
Hi all,
How can I do the following:
Say that I start with a vector with the elements [5 3 4 9 10] - think of these numbers like daily stock prices. I want to transform this vector into (an approx.) of intraday stock prices - 1/10 of day.
Therefore my vector should look like [ 5 4.8 4.6 4.4 .4.2 4 3.8 3.6 3.4 3.2 3 3.1 3.2 3.3 3.4 3.5 3.6 3.7 3.8 3.9 4 4.5 5 5.5 6 6.5 7 7.5 8 8.5 9 9.1 9.2 9.3 9.4 9.5 9.6 9.7 9.8 9 10]
THank you!!

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采纳的回答

Charles Martineau
Charles Martineau 2012-5-31
I figured out some other way
x = 0:4; y = [5 3 4 9 10]; >> xnew = 0:.1:4; ynew = interp1(x,y,xnew,'linear');

更多回答（3 个）

Walter Roberson
Walter Roberson 2012-5-31
NewV = interp1(1:length(V), V, V(1):.1:V(end));
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Charles Martineau
Charles Martineau 2012-5-31
Hi Walter,
Thanks for the help but why I am generating a vector of NaN NaN NaN NaN NaN....
I simply created a vector V (3X1) and I get this strange result.
Thanks!

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Ryan
Ryan 2012-5-31
clear i j
elements = [5 3 4]; % Currently what you have
% Matrix containing intraday prices where each row corresponds to the intraday prices for each of the members of elements
intraday = [1 2 3 4 5 6 7 8;1 2 3 4 5 6 7 8;1 2 3 4 5 6 7 8];
j = length(elements);
for i = 1:j
newelements(i,:) = [elements(i),intraday(i,:)];
end
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显示 1更早的评论
Ryan
Ryan 2012-5-31
clear i j
elements = [5 3 4]; % Currently what you have
% Matrix containing intraday prices where each row corresponds to the intraday prices for each of the members of elements
intraday = [1 2 3 4 5 6 7 8;1 2 3 4 5 6 7 8;1 2 3 4 5 6 7 8];
j = length(elements);
for i = 1:j
newelements(i) = [elements(i),intraday(i,:)];
end
[r,c] = size(newelements);
newestelements = reshape(newelements,1,r*c);
I understand that you answered your own question, but I believe that should work. More round about than your approach though!
Charles Martineau
Charles Martineau 2012-5-31
Hi Ryan,
THanks for help! I'll keep your answer in mind. The answer that I got came from StackOverflow

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Ryan
Ryan 2012-6-1
that should read newelements(i,:) = [elements(i),intraday(i,:)];
it is the same as before, it just reshapes it at the end.

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