How to get output object name created by a method in caller workspace inside the method

1 次查看(过去 30 天)
In order to avoid overwriting the object when the property of that object gets an update, the output object only needs to be constructed when it doesn't exist in the caller workspace.
function zo = update(obj, zi)
% obj is an object of a class; while zi & zo are objects of the same class
% different than obj.
if ~exist(zo) % if zo doesn't exist already in parent workspace
zo = const(); % construct object zo
end
zo = func(zi)
end
In the parent workspace, responding to an event of A, an object Y updates its property based on object X.
Y = A.update(X)
So, inside the function (method) definition, the line
if ~exist(zo)
should have been
if ~exist(Y)
How do I know what name (like "Y") the user have assigned "zo" to from within function "update"? In another word, I'm looking for the equivalent of function inputname() for output.
  4 个评论
Stephen23
Stephen23 2018-5-12
编辑:Stephen23 2018-5-14
I don't see why it is required to mess around with output names, nor would this actually help your given example: somehow (and it will not be simple or efficient) determining the name of the output argument does not tell you if that variable has already been defined previously (which is apparently your stated aim). So your approach is likely a red herring anyway.
Personally I would go for a much simpler option in the caller workspace, something like this:
flag = true;
...
if flag
Y = define_object(...);
flag = false;
end
Using a flag will be much more efficient than using exist. You can also easily pass the flag as an input/output argument.

请先登录,再进行评论。

采纳的回答

Jan
Jan 2018-5-12
This sounds like meta-programming: Using an indirect way around the standard channels to provide information. This would work e.g. by parsing the source code of the calling function. But this is far too complicated and prone to errors. Therefore I'm convinced that the best approach to solve your needs is to chose a different design. Provide the required data as inputs instead of digging in the callers workspace.

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Whos 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by