I need to leave values in an array in blank. NaN problem

19 次查看（过去 30 天）
Patricia Alejandra Palacios Romero
评论： Patricia Alejandra Palacios Romero 2018-5-24
Im working with data that should follow some restrictions, for example the water level in a tank is measured in % so it cannot be more than 100, however, due to measurement erros it can be the case that the measurement mark 120 for example. How should I work with this data if I don't want wrong data to mess up further statistic calculations?. Is it correct to leave the data in blank? and if so what should the condition: NaN? Thank you for your help!

请先登录，再回答此问题。

采纳的回答

Alfonso
Alfonso 2018-5-15
If you are saving all the water level values in an array 1xn or nx1 (a row or column vector) , you could delete the incorrect values retreived like this
i=1;
While i<length(data_array) % Recorremos array con valores de nivel de agua
if data_array(i)>100 % si es mayor al max se elimina
data_array(i) = [] ; %vaciamos/eliminamos el valor
end
i=i+1;
end
  5 个评论
显示 3更早的评论
Guillaume
Guillaume 2018-5-17
I recieved an error message in this part of the code:
Your implementation has the same issue as Alfonso's algorithm. Your i will become out of sync with the actual rows once you've deleted something. In addition, you're trying to delete a single element in a row of a matrix, which is not possible. What you want to do is to delete the whole row.
The efficient and safe way to do that in matlab:
B = A;
B(any(B(:, [5, 20, 23]) > qin250, 2), :) = []; %delete all rows for which any of column 5, 20 or 23 is greater than qin250

请先登录，再进行评论。

更多回答（1 个）

Steven Lord
Steven Lord 2018-5-17
If you use NaN or missing (which for numeric arrays are the same thing) to represent the missing data in your data set, you can use some of the functions designed for handling missing data to remove, replace, or perform computations ignoring the missing data.

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by