how to make if statement repeat only once ?

39 次查看(过去 30 天)
hello I am currently doing a project with matlab and simulink.
In my project I am taking current samples from matlab function and making is statment for a switch .
the problem is that my statment is working all the time , meaning that for exmaple my switch is on "1" and it is switching to "0" I want it to stay like this and not creak the statement again how is it possible ?
function [final_resolt]=relay_condition(u)
format long;
i_diff_1=u(1)-u(4);
i_diff_2=u(2)-u(5);
i_diff_3=u(3)-u(6);
ind_1=u(1)*u(4);
ind_2=u(2)*u(5);
ind_3=u(3)*u(6);
I_diff_1=0;
I_diff_2=0;
I_diff_3=0;
IND_1=1;
IND_2=1;
IND_3=1;
m=20;
I_min=1000;
for i=1:1:m
I_diff_1=(I_diff_1+i_diff_1^2);
I_diff_2=(I_diff_2+i_diff_2^2);
I_diff_3=(I_diff_3+i_diff_3^2);
IND_1=(IND_1*ind_1)/1;
IND_2=(IND_2*ind_2)/1;
IND_3=(IND_3*ind_3)/1;
end
I_diff_1=(I_diff_1/m)^0.5;
I_diff_2=(I_diff_2/m)^0.5;
I_diff_3=(I_diff_3/m)^0.5;
IND_1=IND_1/m;
IND_2=IND_2/m;
IND_3=IND_3/m;
if (I_diff_3>I_min )
final_resolt=0;
else
final_resolt=1;
end
end
  3 个评论
Stephen23
Stephen23 2018-5-17
编辑:Stephen23 2018-5-17
tomer polsky's "Answer" moved here:
Ye this exactly what I want to do . u are currents from simulink and the final resolt is the switch . I want it to change only when time , when it changes to zero stay in this condition.
Guillaume
Guillaume 2018-5-22
Since the if statement is outside of any loop, it will execute only once. Hence it's not clear what the problem is.

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回答(1 个)

Aakash Deep
Aakash Deep 2018-5-22
Hey,
From your question, I understand that you have a if condition inside a loop which you need to execute only once for a particular condition. In order to do this you can use a flag variable. Let's see this with an example, let's suppose you have an array with values 0 and 1. You have to subtract value x only on the first zero in the array.
arr = [1,1,1,0,0,1,0,0];
flag = 0;
for i = 1:len(arr)
if( flag == 0 && arr(i) == 0 )
arr(i)= arr(i) x;
flag = 1; % important part
end
% loop_continue
end
Hope this helps
Thanks,
Aakash Deep

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