Integrate Results of 3D FEM on mesh with arbitrary integration limits

2 次查看(过去 30 天)
I have results of a 3D finite element analysis stored as a list of points [x,y,z], and corresponding values V. I would like to perform 3D integration on small sub-regions of the mesh, using a piece-wise linear interpolation of this data.
I would like to be able to specify a cube in which to integrate the interpolated solution. If a portion of the cube lies outside the mesh, I would like the interpolator to return 0, instead of NaN.
I have tried the below solution, but it throws a warning (see below) and returns 0 when the integration region hangs outside the mesh. It does work on internal regions, but it is very slow (~15 seconds per integration, n_nodes ~40,000), and n_pts is ~1000. This will eventually be wrapped in lsqnonlin() for parameter estimation, so it needs to run relatively quickly for multiple iterations.
function v = RemoveNans(Si,X,Y,Z)
v = Si(X,Y,Z);
v(isnan(v)) = 0;
end
nodes = csvread('nodes.csv'); %3D location of points, irregularly spaced, size = [n_nodes,3]
vals = csvread('values.csv'); %solution to FEM at above nodes, size = [n_nodes,1]
int_pts = csvread('int_points.csv'); %list of points to integrate over, size = [n_pts,3], n_pts << n_nodes
R = 1; %size of cube for integration
Si = scatteredInterpolant(nodes, vals, 'linear', 'none')
f = @(X,Y,Z)RemoveNans(Si,X,Y,Z);
integrated_values = zeros(size(int_pts));
for i=1:length(integrated_values)
integrated_values(i) = integral3(f,...
int_pts(i,1)-R/2,int_pts(i,1)+R/2,...
int_pts(i,2)-R/2,int_pts(i,2)+R/2,...
int_pts(i,3)-R/2,int_pts(i,3)+R/2);
end
"Warning: Reached the maximum number of function evaluations (10000). The result passes the global error test."
Any help on getting this to work properly, or a "better" way to do this would be very helpful.

回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Calculus 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by