Why is my MATLAB plot wrong?
显示 更早的评论
Hi! I just started my Matlab course and i have run into a little problem which i hope you can help me with. I am suppose to write a function which integrates a function e^(-t^2) from 0 to some x which is a variable in the function. I did that like this:
function y = simpson_method(x)
y1 = exp(-0.^2);
y2 = exp(-(x).^2);
c = 0;
d = 0;
incr = 0.1;
for i = 1 : (x - 0)/incr - 0.5
y = exp(-(0 + i*incr).^2);
if i/2 == floor(i/2)
d = d + y;
continue
else
c = c + y;
continue
end
end
y = incr/3 * (y1 + 4*c + 2*d + y2);
The function integrates correctly and gives me a desired output for every x. But the problem is when i try to plot it:
x = 0:0.1:15;
y = simpson_method(x);
plot(x,y)
It gives me the wrong graph which i find weird because all the outputs are correct. I get this which is nonsense. Whats happening?

%
5 个评论
Adam
2018-5-18
What is the right graph?
And what are the values of y that you get out?
Edward Lisa
2018-5-18
Stephen23
2018-5-18
@Edward Lisa: can you please confirm the ambiguous syntax:
- e^((-t)^2)
- e^(-(t^2))
Edward Lisa
2018-5-18
Adam
2018-5-21
If your y values are correct I can see no reason at all why plot would not give the correct answer so your y values cannot be correct if you are literally just calling plot.
回答(1 个)
KALYAN ACHARJYA
2018-5-21
编辑:KALYAN ACHARJYA
2018-5-21
0 个投票
Shown Graph the x ranges are different

类别
在 帮助中心 和 File Exchange 中查找有关 Programming 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
