Display the calculation result

3 次查看(过去 30 天)
Dear :
I have 4(declared for cont) datas of weight,my code is following:
clc
clear all
weight=[1 1 1 1;2 2 2 2;3 3 3 3;4 4 4 4];
ax=[1 2 3 4;1 2 3 4;1 2 3 4;1 2 3 4];
Beta=[0 0 0 0];
cont=length(weight);
for cont_I=1:cont
Etotalx=zeros(cont,cont_I);
for g=1:4
Etotalx(:,cont_I)=Etotalx(:,cont_I)+weight(cont_I,g).*ax(:,g)*exp(1j*Beta(g));
end
end
But the display result only has the last result(the 4th data),others(the former ones) are 0.
The result like this picture:
This is my problem,need everyone's instruction and advice,thank for first.

采纳的回答

Shrestha Kumar
Shrestha Kumar 2018-5-21
Hi, You are declaring a zero matrix each time inside the loop i.e for the first iteration you declare a 4*1 zero matrix and then update the first column, in the second iteration you declare a 4*2 zero matrix and update only the second column and the first column remains zero and so on. The solution for the problem is to declare a 4*4(i.e cont * cont) zero matrix outside the loop and then update the columns.
Etotalx = zeros(cont,cont); for cont_I = 1:cont for g=1:4 ....
  1 个评论
Zoe Lin
Zoe Lin 2018-5-21
编辑:Zoe Lin 2018-5-21
Dear Shrestha Kumar:
Thanks a lot,thank you for your big help,thanks~

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Numerical Integration and Differential Equations 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by