Read files in a specific order
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Hi, I have a series of files named with a date, for every third hour i.e. "NUM_1985_6_4_0_0.dat", "NUM_1985_6_4_3_0.dat", "NUM_1985_6_4_6_0.dat" ,....., "NUM_1985_6_4_21_0.dat",......, "NUM_1985_6_10_21_0.dat", "NUM_1985_6_11_0_0.dat". I'm using the dir command before using the fopen command. Is there any option when using the dir command to be able to list the files on a specific order. I would like to read the files by dates, however, the dir command gives me a list of files where the first one is "NUM_1985_6_10_0_0.dat" following a different logic, where the number 1 goes first in the list.
Thanks
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Stephen23
2018-5-23
编辑:Stephen23
2021-4-18
Download my FEX submission natsorfiles, which was designed to fix the exact problem that you are having. Use it to simply sort the output from DIR:
D = '.'; % folder path
S = dir(fullfile(D,'*.dat'));
S = natsortfiles(S); % alphanumeric sort by filename
for k = 1:numel(S)
F = fullfile(D,S(k).name)
... import/process file F
end
Here is natsortfiles used on your example filenames:
>> C = {'NUM_1985_6_4_0_0.dat';'NUM_1985_6_4_3_0.dat';'NUM_1985_6_4_6_0.dat';'NUM_1985_6_4_21_0.dat';'NUM_1985_6_10_21_0.dat';'NUM_1985_6_11_0_0.dat'};
>> C = C(randperm(numel(C))) % "random" order
C =
NUM_1985_6_11_0_0.dat
NUM_1985_6_4_0_0.dat
NUM_1985_6_4_21_0.dat
NUM_1985_6_4_3_0.dat
NUM_1985_6_4_6_0.dat
NUM_1985_6_10_21_0.dat
>> D = natsortfiles(C) % alphanumeric sort
D =
NUM_1985_6_4_0_0.dat
NUM_1985_6_4_3_0.dat
NUM_1985_6_4_6_0.dat
NUM_1985_6_4_21_0.dat
NUM_1985_6_10_21_0.dat
NUM_1985_6_11_0_0.dat
4 个评论
Luke Riddell
2021-6-22
Hi Stephen,
I've tried this but I get an error returning.
When using:
S = dir(fullfile(FinalFolderloc,'*.ASC'))
S = natsortfiles(S)
It returns the error in line with the natsortfiles function:
" Error using bsxfun
Non-singleton dimensions of the two input arrays must match each other.
mat(logical(bsxfun(@eq,vec,nmn).')) = fnm; % TRANSPOSE bug loses type (R2013b)"
Do you have any advice?
更多回答(1 个)
Rik
2018-5-23
You can sort the output or dir any way you like. See below for an example.
filelist=dir('NUM_*.dat');
dates=[filelist.datenum];
[~,order]=sort(dates);
filelist=filelist(order);
3 个评论
Stephen23
2018-5-23
编辑:Stephen23
2018-5-23
This is a very fragile solution, because it assumes that the files themselves were written in the same order as the data was recorded: this will break easily, e.g. any time a file is edited, or if the files are copied from one folder to another.
"Can we sort the name field from dir?"
Yes. See my answer to know how.
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