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I would like to replace NaN value (in 1 row and 306 columns ) instead of empty matrices inside a cell array of 6804 elements

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velmurugan
velmurugan 2018-5-24
编辑： KSSV 2018-5-24
I had attached a screen shot of my cell array. I need to replace 1*306 double NaN values instead of empty [] cells. Any help would be appreciated. Thank you so much in advance.
I tried the following code:
c= 6804*1 cell
empties = cellfun('isempty',c);
c(empties) = {NaN};
But it just replace the empty cell with single NaN value

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KSSV
KSSV 2018-5-24
编辑：KSSV 2018-5-24
c = cell(5,1) ;
for i = [1 2 4]
c{i} = rand(1,3) ;
end
empties = cellfun('isempty',c);
c(empties) = {NaN(1,3)} ;

更多回答（1 个）

TAB
TAB 2018-5-24
c(empties) = {NaN(1,306)};

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