Why don't i get a vector for phi1?

2018 5 24

1 个回答

1 次查看（30 天）

0 个投票

t = pi/2:0.01:2*pi+(pi/2);

phi1 = (a^2+a^2+d^2+2*a*d*cos(pi-t)-d^2)/(2*b*sqrt(a^2+d^2+2*a*d*cos(pi-t)));

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

Mischa Kim 2018-5-24

编辑：Mischa Kim 2018-5-24

0 个投票

All constants need to be defined. Then use:

 t    = pi/2:0.01:2*pi+(pi/2); 
 phi1 = (a^2+a^2+d^2+2*a*d*cos(pi-t)-d^2)./(2*b*sqrt(a^2+d^2+2*a*d*cos(pi-t)));
 plot(t, phi1)

t is a vector, therefore, you need to use the ./ operator.

R2018a

Find the treasures in MATLAB Central and discover how the community can help you!