How to do this addition?
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D = [60,600,15];
A(2) = D(2); -> OUTPUT OF A LOOKS LIKE A = [0,600]
B(3) = D(3); -> OUTPUT OF B LOOKS LIKE B = [0,0,15]
c = A + B;
disp(c);
How to make length of A as 3 and fill in zeros where the index is not used
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Ameer Hamza
2018-5-27
Make A same size as B
A = [A zeros(1, length(B)-length(A))]
and then add
C = A+B;
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