Get difference between array values
显示 更早的评论
Hello, I have an one column array (see below) with logical 0 and 1. I want to get the difference between each value to detect a jump from 0 to 1 and vice versa. I tried:
find(diff(test(:,1))>0.8)
but everytime I get an error named:
Subscript indices must either be real positive integers or logicals.
whos test:
Name Size Bytes Class Attributes
test 2420x1 2420 uint8
I also tried to convert test to logical or int but the problem still exists. Can someone help?
采纳的回答
You have a variable named diff. Delete that variable.
You might like to check all of these:
which test -all
which diff -all
which find -all
更多回答（2 个）
You can't store the difference from 1 to 0 in an unsigned integer; is there a reason you can't just use default double for test? You must use a signed integer, however.
Also, there's no need for the (:,1) subscript expression on a vector, and since the values are integer logicals, there's no need for the >0.8.
ipos=find([0; diff(test)]==10; % positive locations; augment to keep count same as original length
ineg=find([0; diff(test)]==-10; % ditto for negative
3 个评论
leonidas86
2018-5-28
Stephen23
2018-5-28
If test is a column vector then you need to use a semi-colon:
[0;diff(test)]
dpb
2018-5-28
Yeah, intended to fix and forgot...good catch.
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