Hi, i’m new in Matlab and i can’t understand what is the problem using integral, the error occured is First input argument must ne a function handle, thanks for the help.

1 次查看(过去 30 天)
C1=zeros(1,np);
For j=1:np
x1=0;
x=delta; %delta just defined
R_px=@(x) sqrt((dxxp-(c*x+dxx)).^2+(dyyp-(d*x+dyy)).^2+(dzzp-(f*x)+dzz)).^2);
C1(j)=integral((exp(-R_px(x)*ck)./(R_px(x).^3)),x1,x2);

采纳的回答

Shrestha Kumar
Shrestha Kumar 2018-5-31
Hi,
You cannot directly give a expression as a parameter to the integral function.
So you need to define a new function with definition (exp(-R_px(x)*ck)./(R_px(x).^3)) and then provide the handle(name) of the function to the integral function.
  3 个评论

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Mathematics 的更多信息

产品


版本

R2017a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by