cartesian to polar?
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i have tried to turn my values into polar (I need the angle of Ztot) but it's giving me the wrong value. where is my error?
C1Z = -1/(w*C1*1i);
C2Z = -1/(w*C2*1i);
LZ = w*L*1i;
Ztot = 1/((1/(C1R + C1Z)) + (1/(C2R + C2Z)) + (1/(LZ + Rw +Rsns)));
mag = abs(Ztot);
theta = (angle(Ztot));
real = mag;
imag = theta;
[th,r] = cart2pol (real,imag);
1 个评论
Sean de Wolski
2012-6-5
don't overwrite the very useful builtin functions real() and imag()
回答（3 个）
Walter Roberson
2012-6-5
0 个投票
You indicate that you need the angle of Ztot, but you seem to already be calculating that and placing it in theta. And then you are using that angle as if it was a cartesian coordinate ?? Your calculations look to me more like you have polar coordinates that you want to translate to cartesian ?
katerina jablonski
2012-6-5
0 个投票
1 个评论
Walter Roberson
2012-6-5
You can display values to the command window using disp() or fprintf(). You can display simple messages "pop-up" using msgdlg() and related functions. You can display text data in a user interface control area using uicontrol() or uitable(). You can display text data in a graphic drawing area using text(). You can plot lines in a graphic drawing area using plot() or line(). You can plot a polar coordinate graph in a graphic drawing area using polar()
katerina jablonski
2012-6-5
2 个评论
Honglei Chen
2012-6-5
I don't quite get your question. You said you need the angle of Ztot, why isn't it just angle(Ztot)?
Walter Roberson
2012-6-5
Ztot = ((1/(C1R + C1Z)) + (1/(C2R + C2Z)) + (1/(Rw + Rsns + LZ)))^(-1);
Zmag = abs(Ztot);
Zangle = angle(Ztot); %This is the angle in radians
Zdeg = Zangle * 180/pi; %and in degrees if you need that
Zcos = cos(Zangle); %cos of angle, not angle itself
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2012-6-5
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