the program i have written below is showing the following error how can i correct this

Question

OMKAR ACHARJEE 2018-6-5

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评论： OMKAR ACHARJEE 2018-6-5

>> a1 = xlsread('raincn.xls');
a2 = a1(1:length(a1),5:28);
a2 = a2';
a2 = a2(:);
for i = 12:length(a2)
    k24(i) = a2(i)+ a2(i-1)+ a2(i-2)+ a2(i-3)+ a2(i-4)+ a2(i-5)+ a2(i-6)+ a2(i-7)+ a2(i-8)+ a2(i-9)+a2(i-10)+ a2(i-11)+ a2(i-12)+ a2(i-13)+ a2(i-14)+ a2(i-15)+ a2(i-16)+ a2(i-17)+ a2(i-18) + a2(i-19)+ a2(i-20)+ a2(i-21)+ a2(i-22)+ a2(i-23);
    k24 = k24';
end
Subscript indices must either be real positive integers or logicals.

what do i do now ?

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Answer 1

Walter Roberson 2018-6-5

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For a2(i-23) to be valid, the minimum value for i would have to be 24. Instead the minimum in your for loop is 12, leading to (12-23) = -11 as a subscript.