How to compare two matrix and then count each elements?
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The elements of A will be checked and compared with B, with each element count S will increase and with each absence count R will increase.
A=[3 5 7]
B=[1 3 4 5 7]
5 个评论
Paolo
2018-6-6
Can you please clarify what S and R are, and provide an expected output?
Stephen23
2018-6-6
@suchismita: Please give more details, so that we can actually understand what you want.
What does "with each element count S will increase " mean: do you want to count how many elements A has, or how many elements B has, or how many elements of A as in B, or how many elements of B are in A?
What does "with each absence count R will increase" mean: do you mean elements of A missing from B, or elements of B missing from A, or missing from their own (somehow implied) sequences?
suchismita
2018-6-8
Stephen23
2018-6-8
"I want to count how many similar elements are there in A in compare to B"
That is what my answer does. You might also like to read about intersect and setdiff.
suchismita
2018-6-8
采纳的回答
Stephen23
2018-6-6
Some variety of these might do what you want (although those examples are not very enlightening)
>> S = nnz(ismember(A,B))
S = 3
>> R = nnz(ismember(B,A))
R = 3
2 个评论
suchismita
2018-6-9
"but how can I count dissimilar value."
ismember returns a logical array. Negate that array to get the dissimilar values:
~ismember(...)
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Pratik Panchal
2018-6-6
It is not clear whether S and R are increasing if the values of A are same as values of B or regardless. Also what do you mean by 'absence'?
Anyway for the comparison You can use a for loop in this.
for k=1:length(A)
for j=1:length(B)
if A(k)==B(j);
%Insert your condition here
else
%Insert your second condition here
end
end
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