No. You cannot use if to find an error, because an error interrupts and stops execution of your code. However, you can use a try block to do that. Try intercepts any error that occur inside the try block, and immediately transfers execution into the catch block, where you can do as you wish.
try
a = 1:2;
a(5)
catch
disp('you did something wrong')
end
you did something wrong
So, when the try block executed, it assigned a to a vector of length 2. I can verify that a exists, and is of length 2.
a
a =
1 2
But then I did something silly, that will result in an error. Instead of allowing the error to be generated, it traps into the catch block, where I could have done whatever I wanted to, with the code continuing execution there.
No error message was generated. So, while I would have expected to see this:
a(5)
Index exceeds array bounds.
Instead, it dropped into the catch block. We can extract that error message, if we want to do so though.
lasterror
ans =
struct with fields:
message: 'Index exceeds array bounds.'
identifier: 'MATLAB:badsubscript'
stack: [0×1 struct]
So, you cannot use if. But you CAN use try/catch.
