how I Found the minimum of function using the fminbnd ??

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ahlem sellami
ahlem sellami 2018-6-7
编辑： Walter Roberson 2018-6-7
f(x)=3x1+2x1x2+x2 such as 0.1≤ x1 ≤1 0.25 ≤ x2 ≤ 4 help me please thanks in advance

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回答（2 个）

Walter Roberson
Walter Roberson 2018-6-7
You cannot do that. fminbnd() can only be used for a function of a single variable.
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Walter Roberson
Walter Roberson 2018-6-7
fun = @(x) 3*x(1) + 2*x(1)*x(2) + x(2)
x0 = [.5 2.5];
A = [];
b = [];
Aeq = [];
beq = [];
lb = [0.1 0.25];
ub = [1 4];
x12 = fmincon(fun, x0, A, b, Aeq, beq, lb, ub)
x1 = x12(1); x2 = x12(2);

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Torsten
Torsten 2018-6-7
You can't. fminbnd is for functions of one variable - your f is a function of two variables.
Use "fmincon" instead.
Best wishes
Torsten.
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Torsten
Torsten 2018-6-7
In principle, x0 is arbitrary.
But if you know an x0 that is feasible and near to the optimum, you should use it since you'll most probably get faster and more stable convergence towards the solution.

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