how can i plot "L(1) L(2)*cosd(t) -

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Dwaipayan Roy
Dwaipayan Roy 2018-6-8
评论： Dwaipayan Roy 2018-6-8
How can i plot "L(1) + L(2)*cosd(t) - L(3)*cosd(j) = cosd(t - j)" between t and j, given L(1),L(2),L(3) are constants? Please help someon
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Torsten
Torsten 2018-6-8
And your constants L(1), L(2) and L(3) are such that your equation always has a solution for t, given j ?
Dwaipayan Roy
Dwaipayan Roy 2018-6-8
It's within a certain limit. I give xi and xf and t=xi:0.1:xf such that it will have a solution. It's for a four bar linkage synthesis

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Torsten
Torsten 2018-6-8
xi=...;
xf=...;
L = [... ;... ;...];
T = xi:0.1:xf;
J = zeros(numel(T),1);
for i=1:numel(T)
t = T(i);
fun=@(j) L(1)+L(2)*cosd(t)-L(3)*cosd(j)-cosd(t-j);
j0 = 1.0;
J(i) = fzero(fun,j0)
end
plot(T,J)

更多回答（1 个）

Aquatris
Aquatris 2018-6-8
You can use;
syms x y
ezplot(4+5*cos(x)-6*cos(y) == cos(x-y))
where x and y are in radian instead of degree.

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