How to make this plot

1 次查看（过去 30 天）
Stefano Di Vito
Stefano Di Vito 2018-6-11
评论： Stephen23 2018-6-12
Hello everyone, thanks in advance for your time and help! I'm going to expose my situation:
I've got a logical matrix, of dimensions, let's say, (P,T). For istance:
P=4;
T=3;
M=[1 1 0 0 ;1 1 1 0; 1 0 0 0];
I should make a plot on the plan of axis T (x-axis) and P (y-axis), as it follows. For each fixed T, i should obtain a vertical bar which stands from P=1 to P=4. This bar should be a two-tone bar: it should be composed of a red-colour part, as extended as the number of values 1 occurring in the correspondant column of the matrix M. The remaining segment should be green, as extended as the number of values 0 occurring in the correspondant column of the matrix.
For istance, fixed T=1, i should get a red line from P=1 to P=2 and a green line for the remaining values of P; fixed T=2, i should have a red line from P=1 to P=3 and a green part for P=4, and so on.
Substantially, i need to repeat this for each T ( i fix the column of the matrix and plot P-values for that column) and put all the vertical lines in the same plot ( should i use hold on ?). The red lines' length should be equal to the number of 1 values occurring in the columns. The green lines' length should be equal to the number of 0-values (remaining values) occurring in the columns.
I've been trying a lot, but can't get which should be the right plot function to be used. Thank You for helping me!
  3 个评论
显示 1更早的评论
Stefano Di Vito
Stefano Di Vito 2018-6-11
That's perfect, thank you. To solve all my doubts, is there a way to get this image with the borders of each bar (without getting blank spaces between them)?
Stephen23
Stephen23 2018-6-12
"is there a way to get this image with the borders of each bar"
Not really. You could with a lot of fiddling around, but it would not be worth it. That is why I put this as a comment, not an answer: it is mostly for interest.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Sandro Lecci
Sandro Lecci 2018-6-11
Hi Stefano,
Is this what you are trying to do?
if yes then this is the code:
P=4;
T=3;
M=[1 1 0 0 ;1 1 1 0; 1 0 0 0];
myData = sum(M,2);
dataToPlot = [myData, size(M,2)-myData];
figure();
handle_bar = bar(dataToPlot, 'stacked');
handle_bar(1).FaceColor = 'r';
handle_bar(2).FaceColor = 'g';
xlabel('T')
ylabel('P')
The trick is to create a matrix with T lines and 2 columns, the first column stores the number of ones in your M matrix and the second column stores the number of zeros in M (or, as in my code, the difference between the second dimension of M (which is 4) and the number of ones). You then plot everything using the bar function, specifying that you want the columns of "myData" to be stacked. Then you use the created handle (handle_bar) to access the FaceColor of the first column (in red) and the second column (in green).
Best, Sandro
  4 个评论
显示 2更早的评论
Stefano Di Vito
Stefano Di Vito 2018-6-11
Excuse me, i noticed you set the script in order to get a matrix of T lines and 2 columns, but i think i need a matrix of P lines. I'll explain in a better way. T are the time windows, so i should put these on the x-axis (like a time series graph). On the other hand, for each T (time window) i should plot a bar of length equal to P, which is two tone, as i explained in the previous message. Essentially, i need a graph like the one in the image (in which P=80, T=155), but with visible borders for each bar.
Sandro Lecci
Sandro Lecci 2018-6-12
In my script the T are on the X axis, right? There are three time windows (T = 3). In the end I get a matrix of T lines (that go on the x axis) and 2 columns, identifying the size of each red-green part of that specific column).
I am not experienced with the solution of M. Cobeldick, using bars one should simply set the barwidth to 1 (default is 0.8 I guess).
handle_bar = bar(dataToPlot, 'stacked', 'barwidth', 1);
Best

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Discrete Data Plots 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by